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P1 = (Ïû»ð˨˨¿ÚѹÁ¦+ ¹ÜµÀˮͷËðʧ)- (Ë®Ïäµ×±ê¸ß- ¸ß²ãÂ¥Ãæ±ê¸ß-Ïû»ð˨˨¿Ú¾àµØ¸ß¶È)

= (23.59 + 2.0) - (123.2 - 118.6 - 1.1)

= 22.1 (mH2O)

= 0.221 (MPa ,±íѹ)

= 0.321 (MPa ,¾øѹ)

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È¡¦Â = 1.1 , P0 =P1/¦Â =0.321/1.1 = 0.292 (MPa ,¾øѹ)

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(4) ÔËÓÃÆøÌ嶨ÂɼÆËã¸÷¹¤¿öµãʱ¹ÞÄÚѹÁ¦ÓëÏàÓ¦µÄ¹ÞÄÚ¿ÕÆøÌå»ý¡£

µÍÏû·À¹¤×÷ѹÁ¦P1 ʱ,Æøѹ¹ÞÄڵĿÕÆøÌå»ýV 1 :V 1 =(P0/P1)V =(0.292/0.321) ¡Á1.58 = 1.436 (m3)

ÓÉÓÚ¸ßλÏû·ÀË®Ïäͬʱ¹©¸øÏû»ð˨Óë×Ô¶¯ÅçË®Ãð»ðϵͳ,¹ÊÆøѹ¹Þµ÷½ÚË®ÈÝ»ýV x È¡0145m3 ¡£

¸ß¹¤×÷ѹÁ¦Ï¹ÞÄڵĿÕÆøÈÝ»ýV 2 :V 2 = V 1 - V x = 1.436 - 0.45 = 0.986 (m3)
¸ß¹¤×÷ѹÁ¦P2 :P2 =(V 1/V 2)P1 =(1.436/0.986) ¡Á0.321 = 0.468 (MPa ,¾øѹ)

¸ù¾Ý¾­Ñé,ÎÈѹ±ÃµÄÆô¶¯Ñ¹Á¦PS1È¡Öµ±ÈP2 ´ó0.02MPa ,¼´: PS1= P2 + 0.02 = 0.488 (MPa ,¾øѹ)

 ÔòÎÈѹ±ÃÆô¶¯Ñ¹Á¦Ï¹ÞÄڵĿÕÆøÈÝ»ýV S1:V S1=(P2/PS1)V 2 =(0.468/0.488 )¡Á0.986 = 0.946 (m3)

¼ÆËãʱ,Æøѹ¹ÞµÄ¹¤¿ö»¹Ó¦Âú×ãÒÔÏÂÌõ¼þ:ÎÈѹ±ÃµÄÍ£±ÃѹÁ¦PS2°´PS2= PS1+ 0.05MPaÈ¡Öµ,ͬʱӦ·ûºÏÎÈѹˮÈÝ»ýV S = V S1- V S2²»ÉÙÓÚ0.05m3 µÄ¹æ¶¨¡£

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PS2= PS1+ 0.05 = 0.538 (MPa ,¾øѹ)
V S2=(PS1/PS2)VS1=(0.488/0.538 )¡Á0.946 = 0.858 (m3)
V S = V S1- V S2= 01946 - 01858 = 01088 (m3)> 0105 (m3)

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